Leet Code Daily 2024-07-03 - Minimum Difference Between Largest and Smallest Value in Three Movies

class Solution {
public:
    int minDifference(vector<int>& nums) {
        sort(nums.begin(), nums.end());
        int n = nums.size(), ans = INT_MAX;
        for (int i = 0; i < 4 && i < n; i++) {
            ans = min(ans, nums[max(n + i - 4, i)] - nums[i]);
        }
        return ans;
    }
};